your email address is not working — your post is wrong, email me at sjm1@williams.edu

]]>1. Weigh 6 coins on each arm of scale.

Since 1 coin is either lesser or more heavier compared to one of the other 11 coins with equal weights, then the weighing scale’s arms must be unequal in level after putting 6 coins on each side.

Assuming the heavier group of six coins contains coin X, then

2. we repeat the process, placing 3 coins on each arm and again taking the group that is heavier.

Only 3 coins remain. We took the heaviest group in every weighing we did.

3. Among these 3 coins, choose 2 and put one on each arm of the scale and see if they have the same weight. If yes, replace one coin with the other remaing coin of the last 3 coins. If the coin you placed last causes the scale to change in level, then that is coin x. If it does not caused any changes, we take the other 6 coins we first disregarded and do the same step. ]]>

email me at sjm1@williams.edu — email to you bounced

]]>My email to you bounced — please email me at sjm1@williams.edu

]]>I’ll bump up the difficulty. My dream was to have the site set up so people could vote and adjust the level accordingly.

]]>sadly no

you can’t put 4 on a side and remember the weight as you can only weigh

with items on both sides. //s