let a^x = x^(x^(x^(x^…))…)
so a^x = 2
Take logs of both sides.
ln(a^x) = ln(2)
x*ln(a) = ln(2)
x = ln(2)/ln(a)
But since a is x to the power of x an infinite number of times, a = 2. So ln(a) = ln(2).
Therefore x = 1.
Written by Steven Miller on December 31, 2011.Reply
Anon: you’re close but not quite there — email me at [email protected] if you want to discuss more.
As I’m doing this on my phone please forgive typos and lack of proper notation. As x tends toward infinity then the answer tends toward 1. So the limit of x^x^x = 2 as x tends to infinity is x tending toward 1. Isn’t it??
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